# How much oxygen was spent on the combustion of ethyl alcohol if 0.3 liters of CO2 were released?

October 3, 2021 | education

| To solve the problem, it is necessary to compose the reaction equation:

С2Н5ОН + 3О2 = 2СО2 + 3Н2О – the ethanol combustion reaction is accompanied by the release of carbon monoxide (4) and water;

M (O2) = 32 g / mol; M (CO2) = 44 g / mol;

Determine the amount of moles of carbon monoxide, oxygen:

1 mol of gas at n. y – 22.4 l;

X mol (CO2) – 0.3 liters from here, X mol (CO2) = 1 * 0.3 / 22.4 = 0.013 mol;

0.013 mol (CO2) – X mol (O2);

-2 mol -3 mol from here, X mol (O2) = 0.013 * 3/2 = 0.019 mol;

Let’s calculate the volume of oxygen:

Y (O2) = 0.019 * 22.4 = 0.425 l.

Answer: the reaction requires oxygen with a volume of 0.425 liters.

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